RC India

Guys i have a imax b6ac charger and a 2 lipo batteries ...
Battery : Zippy 5400mah 35C 2S.

New with all this charging and batteries ...
Would have given it a shot by de youtube videos but ad it consists of a Lipo battery I don't want to take a risk.
I want to balance charge ...
How will I know if the battery is full charged ?

I dont own the same charger you own but I own a Accucel 8 which I think is pretty identical .
To charge your 2s lipo go to
Lipo > balance charge > select 2s lipo and start charging .
It must be somewhat like that.

Since you got a new lipo I guess , charge them @2amp

it will auto cut off after full charge and end with an alarm tone

The pics i have attached ... What it exactly looked like and i stopped it when the 8.00V went above as it was a 7,4V battery ..That means 3.7 for each cells and even that was like 4.0
Anyways the batteries are already up for sale cause i have ordered the wrong one & its not able to fit the E-MTA :(
Will get a new battery next week and carry on from the above reply :)
Just explain me this Volt thing ...
On that picture was it over charging or was it going normal.

No problem . Everything is fine

It's 3.7v each cell when Discharged . Overall 3.7v x 2 = 7.4v

It's 4.2v each cell when full charged . Overall 4.2 x 2 = 8.4v

So your charger will charge upto 4.2v each cell for full charging .

Ok so got new batteries Venom 5200Mah ...
What i have read about IMAX B6AC charger is that the amperage rates are calculated as your battery size divided by 1000.
Like mine is a 5200MAH battery so divided by 1000 will be 5.2A ... But my imax charger shows me A only till 5A MAX...
What should be the A while charging for mt battery ... So confused.

Charge the battery at 5000mah (5A) closer to 1C.

Ok thats what i am charging them in from the past 1 hour and its still charging .. does it take this long

It's stuck at 8.20V and then 8.22 doing this from a long time ... "A" was set at 5A but it sets that automatic below 1A ...
Am i doing anything wrong ... or it's cause of using a 50W charger for a 5200mah battery ?
Need help guys this thing z drivn me crazy from weeks :(
I have attached the pics below

Relax. Its ok.
1c charge is supposed to take 1 hour.
However as the voltage approaches full charge, the charger reduces the current.
Your cells are presently out of balance.
Disconnect, reconnect and try using Balance option instead of Charge.
The charger will probably allow max 0.5a for balancing.
Be patient and in 15-20 minutes you will find both cells equal at about 4.20.
If not, then one cell probably not up to the mark.
If need be, use storage option to bring both down to about 3.85, then charge.
Check that battery is not heating up.
Best of luck.

First of all you need to understand and learn the basics of electricity before handling with electric components. As it seems that you have little or no clear understanding of it, let me put it for you as simple as it could be.

Power is measured in watts denoted as 'W'.
Rate of Current flow is measured in Amperage/Amps denoted 'A'.
Force of the electricity is measured in Volts denoted 'V'.

Power is the resultant of multiplication of Current flow and and Force, ie., V x A or simply VA. So the formula for power is W = VA.


With your query here, the battery is rated for 5200mAh. Since you have not mentioned the number of cells, I assume it as 2S, ie., 3.7V x 2 = 7.4V. [the alphabet 'S' denotes that the preceding number, here 2, has two cells connected in Series]. Connecting two or more cells in series will add the voltage of those connected cells with the average Current.

Also notice that the small letter 'm' denotes it is in milli [1/1000th] of the 'A', rated for one hour denoted by 'h'. So your battery can discharge 5.2 amps of current at 7.4 volts for a duration hour.

There is one more rating for batteries, called the charge/discharge rate, denoted by 'C'. It specifies the safe max margin for usage. Say, if the battery has 10C for discharge and 2C for charge, then you can discharge or load it upto 10 times its normal discharge, ie., 5.2Ax10C = 52A. But this will lower the charge holding time to 1/10. Similarly for charging, you can set the charging current to 5.2Ax2C = 10.4A with the charging voltage normally 10% more than its rated 'V', so thereby you can cut down the charging time by 1/2.