Hi everyone,
In the 'Tech Talk - How much power' thread,
Rai saheb raised a 64 million $ question - how to predict the rpm (and therefore voltage)drop under load!

Could not answer right away for the simple reason that i didn't know!

However, after some head scratching, and actual testing, here is my attempt at an answer.
Grateful for scrutiny to see if the following analysis is reasonably correct.

Obviously, the voltage drop under load is a function of the current drawn and the internal resistance of the battery

To check this relationship, I connected a known load (55w 12v car halogen bulb) to 3 different 3s 2200mah lipos via the HK-010 Power Analyzer. Results were as follows:

Make       Watts   Amps   Volts      Volts       Volts   IR milliohm
                                     NoLoad  Loaded    Drop     
Haiyin        58.7    4.8     12.43     12.24      0.21      44
Turnigy1     54.1    4.7     12.04     11.78      0.26      55
Turnigy2     48.0    4.4     11.45     10.93      0.52     118

Haiyin from Vishal Rao of Kinetic Hobbies. About 3 months old, less than 10 cycles, only 1 flight.
Turnigy1 about 6 months old, about 20 cycles.
Turnigy2 about 12 months old, only 2-3 cycles, but bloated probably due to having been stored for several months on full charge.
All three rated 20-30c.

(Since this was only a preliminary investigation, please ignore for the time being, issues like all 3 batteries not being at the same starting voltage, the wattage not being exactly 55w etc)

Using the above IR figures, and assuming a 20amp draw, we can expect the following voltage under load:

Make          Volts      Amps     IR       Volts      Volts
                  NoLoad                         Drop      OnLoad
Haiyin         12.50       20        44      0.88      11.62
Turnigy1      12.50       20        55      1.10      11.40
Turnigy2      12.50       20       118     2.36      10.14 (ie, it can't take a 20amp load!)

Assuming
1. 1000kv
2. Actual rpm / kv x voltage of say 75% (Not a rule, only a thumb rule)

On a 20amp load, one could expect about:
8700 rpm with the Haiyin
8550 rpm with the Turnigy1
7600 rpm with the bloated Turnigy (before it dies...)

Will test to see if these estimates are any good, and whether there are any blatant errors in the analysis.

This is a very very rough extrapolation sir. It needs more precision. I think we have to first derive the "apparent load of the motor/prop"  ie an equivalent resistance connected in series over which there will be a potential drop. But I am not sure myself, that's why I asked

Sir,
$64m ke liye kafi sir khujlana pada
The old grey cells ain't what they used to be.

Where are our young Electrical fellows? Busy overcharging?

Sir,
More importantly than precision (which I will refine),
I request an opinion on whether the approach to the problem is correct from the theory point of view.
Or is it funda gol?

With due deference sir, it is an incorrect approach.

One should be trying to identify the physical phenomena rather than looking for number patterns, ie Deductive rather than Inductive reasoning

Iyer sir...  Great thread...
I feel it's a good beginning... And if we could just add a Tachometer to the above setup...
We could get to know the output power... Which could be the equated with the input power...  We should be able to get the voltage drop ( ignoring power loss due to friction.. Heat etc) 
Sir please correct me if am wrong

How does the tacho help in detrmining power here?

The Power output can be calculated with a prop rotating at a know RPM...  Tachometer would help us get the actual RPM hence the power output... .. Correct me if am wrong

How? How will knowing rpm alone give you power? Power = torque x rpm. How will you measure torque?

We can get the power by...

Or better way use one of the many webcalc available..

How will you measure Vo?

Doc, this is simply argument for the sake of it. Disappointing.

Sir... Please...  This formula is for dynamic thrust.. Label V0 as nil and you should get static thrust...
I really don't argue just for the heck..I know more then often  I am wrong... But I learn... And that's what am here for learning... And who else can be a better teacher than a person like you... Bow

This will give you thrust. How will you get power

Sir I sincerely don't know the formula but there are a few webcalc, that I routinely use...
Here's one..
http://adamone.rchomepage.com/calc_thrust.htm

Iyer Sir  ' SOS '

@docnayeem,
Sorry for delay. Was out flying!

Looks like i got too intrigued by Rai Saheb's $64m question, and too involved in trying to find an answer for something i didn't know.
In retrospect, i realise that i was on a wild goose chase, and barking up the wrong tree, in the process missing the woods for the trees!

The real issue is:
Why would i (or anyone) need to PREDICT the voltage drop/rpm loss under load?

I don't need to predict it, as i already know!
I just run the motor with a given prop (and different props) on my test rig, (which has a tach)
and it TELLS me:
- the voltage without load
- the voltage under different loads at different rpms
- the amperage under different loads at different rpms
- the rpm under different loads at different throttle positions
- the duration of the run
- the mah consumed in the duration of the run
- the thrust under different motor/ prop/ rpm/ power conditions

And i know the pitch speed from the rpm.
And the gms thrust per watt of power for different motor/prop combos at different rpms.

Can't think of anythink else i need.

Looks like i've utterly failed to understand the significance of the question!
As i said earlier, my old grey cells ain't what they used to be!

So the only outcome of this effort is that i could find out the internal resistance of some of my batteries.
That is something i didn't know earlier. Now i'll check all of them.
Regards

Iyer sir. Measurement imho is the only way. Just use a voltmeter

But sir, for that many of us have test rigs

The question was directed in the context of some issues that had come up, wherein one without a wattmeter etc. and without experience to make a reasonably accurate guesstimate, could predict, thus helping him or her to select a suitable prop for the given motor for the given model

Hope you agree that 'selecting a suitable prop' is a subset of 'How much power is required' and 'pitch required'

Precisely the questions i tried to address in my first Tech Talk - for precisely the same audience!

Glad we are on the same wavelength!

@docnayeem
Sir, I don't know whether you can calculate power or not, but even if you find the power, these motors have an efficiency of only 60-70%, Lower kv motors may go up to 80 or 85%, but even that is not small enough to neglect.
So your calculation of voltage drop will be incorrect. Correct me if I'm wrong.

@maahinberi,
@docnayeem
Taken as 75% in the first post.