0.46 engine review
http://www.rcuniverse.com/magazine/article_display.cfm?article_id=1016So, a 0.46 ci (Cubic Inch)[=7.5 cubic centimeter] engine gives 1.16HP
Therefore a 2KW engine should be sufficient for that.
Now a low KV motor need more turn for less KV.
Now for taking MMF being same, NI (no. of conductor x Current) be same.
Again, as turn increases, current decreases per conductor.
But electrically to keep same power, voltage should be higher. [power = volt x amp.]
Again higher turn gives higher backemf and so supply voltage should be higher.
So, go for a 4-6S motor of low KV. and use maximum voltage supported by the motor, always to take more output.
0.60 = 1.68 HP [at 16000 rpm i. e. 266rps]